ip-address interview questions
Top ip-address frequently asked interview questions
I have a script that is to be run by a person that logs in to the server with SSH.
Is there a way to find out automatically what IP address the user is connecting from?
Of course, I could ask the user (it is a tool for programmers, so no problem with that), but it would be cooler if I just found out.
Source: (StackOverflow)
What is the most efficient way to store and retrieve IP addresses in MySQL? Right now I'm doing:
SELECT * FROM logins WHERE ip = '1.2.3.4'
Where ip is a VARCHAR(15)
field.
Is there a better way to do this?
Source: (StackOverflow)
If you need to locate a user based on their IP address, what services are available (free and not free services are fine)?
P.S. I understand that some users use proxies etc., that means the result is not 100% accurate. That's ok.
Source: (StackOverflow)
I'm making a website where users can log on and download files, using the Flask micro-framework (based on Werkzeug) which uses Python (2.6 in my case).
I need to get the IP address of users when they log on (for logging purposes).
Does anyone know how to do this? Surely there is a way to do it with Python?
Source: (StackOverflow)
When using socket.IO in a Node.js server, is there an easy way to get the IP address of an incoming connection? I know you can get it from a standard HTTP connection, but socket.io is a bit of a different beast.
Source: (StackOverflow)
I need to store the IP address of the users who comment, in the database after form submission.
Is there any symfony2 function to get the IP? Or any other way to get the IP?
Source: (StackOverflow)
I need to get local IP of computer like 192.*....
Is this possible with PHP?
I need IP address of system running the script, but I do not need the external IP, I need his local network card address.
Source: (StackOverflow)
In Rails 2.3.2, what's the best way to get the ip address of the client connecting to the server?
Here are two ways I've found:
request.remote_ip
request.env['HTTP_X_REAL_IP']
Source: (StackOverflow)
I have XAMPP installed in local laptop. And I have a almost static ip. I would like to give the ip to other to run it from thier browser. I configured apache httpd-vhosts.conf to listen my ip address:80 and added the virtual server with the ip address and domain root to local httdocs directory and the servername as localhost.
Apache doesn't start. what should I do to access my website from external computer.
THnks
Source: (StackOverflow)
I know regex is dangerous for validating IP addresses because of the different forms an IP address can take.
I've seen similar questions for C and C++, and those were resolved with a function that doesn't exist in C# inet_ntop()
The .NET solutions I've found only handle the standard "ddd.ddd.ddd.ddd" form. Any suggestions?
Source: (StackOverflow)
This question already has an answer here:
What's the best way to validate that an IP entered by the user is valid? It comes in as a string.
Source: (StackOverflow)
I understand it's a standard practice to look at both these variables. Of course they can easily be spoofed. I'm curious how often can you expect these values (especially the HTTP_X_FORWARDED_FOR
) to contain genuine information and not just be scrambled or have their values stripped away?
Anyone with the experience or statistics on this stuff?
Is there anything else that can be useful for the task of getting the client's IP address?
Source: (StackOverflow)
This question already has an answer here:
What should be the most recommended datatype for storing an IPv4 address in SQL server?
Or maybe someone has already created a user SQL data-type (.Net assembly) for it?
I don't need sorting.
Source: (StackOverflow)
I'm not too sure how to go about getting the external IP address of the machine as a computer outside of a network would see it.
My following IPAddress class only gets the local IP address of the machine.
public class IPAddress {
private InetAddress thisIp;
private String thisIpAddress;
private void setIpAdd() {
try {
InetAddress thisIp = InetAddress.getLocalHost();
thisIpAddress = thisIp.getHostAddress().toString();
} catch (Exception e) {
}
}
protected String getIpAddress() {
setIpAdd();
return thisIpAddress;
}
}
Source: (StackOverflow)